MCQ
${(1 - 2x)^{3/2}}$ ના વિસ્તરણમાં ચોથું પદ મેળવો.
- A$ - \frac{3}{4}{x^4}$
- ✓$\frac{{{x^3}}}{2}$
- C$ - \frac{{{x^3}}}{2}$
- D$\frac{3}{4}{x^4}$
$ = 1 + \frac{3}{2}( - 2x) + \frac{3}{2}.\frac{1}{2}.\frac{1}{2}{( - 2x)^2} + \frac{3}{2}.\frac{1}{2}\left( { - \frac{1}{2}} \right)\frac{1}{6}{( - 2x)^3} + .....$
Hence ${4^{th}}$ term is $\frac{{{x^3}}}{2}$
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