MCQ
$1 \,amu$ is equal to
- ✓$\frac{1}{{12}}{\rm{\,of \,}}C - 12$
- B$\frac{1}{{14}}{\rm{\,of \, O - 16}}$
- C$1\,g\,{\rm{ \,of \,}}{H_2}$
- D$1.66 \times {10^{ - 23}}\,kg$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$C{H_3} - C \equiv C - H\xrightarrow{{NaN{H_2}}}\xrightarrow{{C{H_3} - I}}(A)\xrightarrow{{Li/liq\,N{H_2}}}(B)$
$C{H_3} - C \equiv C - H\xrightarrow{{NaN{H_2}}}\xrightarrow{{C{H_3} - I}}(A)\xrightarrow[{Pd.CaC{O_3}}]{{{H_2}}}(C)$