MCQ
$1$ mol of $C{H_4}$contains
- A$6.02 \times {10^{23}}$atoms of $H$
- ✓$4 \,g$ atom of Hydrogen
- C$1.81 \times {10^{23}}$molecules of $C{H_4}$
- D$3.0 \,g$ of carbon
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| $A[M]$ | $B[M]$ |
initial rate of formation of $D$ |
|
| $i$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
| $ii$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
| $ii$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
| $iv$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
Based on above data, overall order of the reaction is $\qquad$
$\left[\right.$ Given $\left.: \log _{10} 2=0.301, \ln 10=2.303\right]$
$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(0.02 \mathrm{M}) \rightarrow \mathrm{Zn}^{2+}(0.04 \mathrm{M})+\mathrm{Cu}(\mathrm{s})$
$\mathrm{E}_{\text {cell }}=...... \,\times 10^{-2} \,\mathrm{~V} { (Nearest integer) }$
${\left[\text { Use }: \mathrm{E}_{\mathrm{Cu} / \mathrm{Cu}^{2+}}^{0}=-0.34\, \mathrm{~V}, \mathrm{E}_{2 \mathrm{n} / \mathrm{Zn}^{2+}}^{0}=+0.76 \,\mathrm{~V}\right.}$
$\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059\, \mathrm{~V}\right]$
$3,4,5-$Tribromoaniline $\underset{\text{(ii) }{{H}_{3}}P{{O}_{2}}}{\mathop{\xrightarrow{\text{(i) diazotization}}}}\,\,?$
$(A)$ tert-butanol and $2$-methylpropan-$2$-ol
$(B)$ tert-butanol and $1$, $1$-dimethylethan-$1$-ol
$(C)$ $n$-butanol and butan-$1$-ol
$(D)$ isobutyl alcohol and $2$-methylpropan-$1$-ol