$10$ resistors, each of resistance $R$ are connected in series to a battery of $emf$ $E$ and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased $n$ times. The value of $n$ is :
NEET 2023, Medium
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$I_S=\frac{E}{10 R}$
$I_P=\frac{E}{R / 10}=\frac{10 E}{R}$
$n=\frac{I_P}{I_S}=100 \Rightarrow n=100$
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