Question
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Number of letters 1-4 4-7 7-10 10-13 13-16 16-19
Number of surnames 6 30 40 16 4 4
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.

Answer

First, we will convert the graph given into tabular form as shown below:
Class interval Frequency ($f_i$) Mid value ($x_i​​​​​​​$) $f_ix_i$ Cumulative Frequency
1 – 4 6 2.5 15 6
4 – 7 30 5.5 165 36
7 – 10 40 8.5 340 76
10 – 13 16 11.5 184 92
13 – 16 4 14.5 58 96
16 – 19 4 17.5 70 100
  N = $\sum$$f_i$ = 100   $\Sigma f_i x_i$ = 832  
  1. N = 100
    Mean = $\frac { \Sigma f_i x_i } { N } = \frac { 832 } { 100 }$ = 8.32
  2. $ \frac{N}{2} = \frac{{100}}{2}$ = 50
    The cumulative frequency just greater than $\frac {N} {2}$ is 76, then the median class is 7 - 10 such that
    l = 7, h = 10 - 7 = 3, f = 40, F = 36
    Median = l + $\frac { \frac { N } { 2 } - F } { f } \times$ h
    = 7 + $\frac { 50 - 36 } { 40 } \times$ 3
    $= 7 + \frac {42} {40}$ = 7 + 1.05 = 8.05
  3. Mode = 3 Median - 2 Mean
    = 3 $\times$ 8.05 - 2 $\times$ 8.32 = 7.51

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