MCQ
$\,$
  • A


  • C

  • D

Answer

Correct option: B.

b

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$\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   H-C-D\xrightarrow{{{H}^{18}}{{O}^{-}}}  \\
\end{matrix}\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   D-C-{}^{18}{{O}^{-}}+C{{H}_{2}}D-OH  \\
\end{matrix}$

Above reaction is known as

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The value of $K _{ C }$ is $64$ at $800\, K$ for the reaction $N _{2}( g )+3 H _{2}( g ) \rightleftharpoons 2 NH _{3}( g )$

The value of $K _{ C }$ for the following reaction is :

$NH_{3}(g) \rightleftharpoons \frac{1}{2} N _{2}(g)+\frac{3}{2} H_{2}(g)$

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$Image$

In this reaction, $\mathrm{RCONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.

$1.$  How can the conversion of $(i)$ to $(ii)$ be brought about?

$(A)$ $\mathrm{KBr}$  $(B)$ $\mathrm{KBr}+\mathrm{CH}_3 \mathrm{ONa}$  $(C)$ $\mathrm{KBr}+\mathrm{KOH}$  $(D)$ $\mathrm{Br}_2+\mathrm{KOH}$

$2.$  Which is the rate determining step in Hofmann bromamide degradation?

$(A)$ Formation of $(i)$  $(B)$ Formation of $(ii)$  $(C)$ Formation of $(iii)$  $(D)$ Formation of $(iv)$

$3.$  What are the constituent amines formed when the mixture of $(i)$ and $(ii)$ undergoes Hofmann bromamide degradation?

$Image$

give the answer question $1$, $2$, and $3.$