MCQ
15C3 + 15C5 + .... + 15C15 will be equal to:
- A214
- B214 - 15
- C214 + 15
- D214 − 1
Solution
We know
15C1 + 15C3 + 15C5 + .....15C15 = 215 - 1
$\therefore$ 15C3 + 15C5 + ... + 15C15 = 214 - 15
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A five digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is.
[Hint: 5 digit numbers can be formed using digits 0, 1, 2, 4, 5 or by using digits 1, 2, 3, 4, 5 since sum of digits in these cases is divisible by 3.]