MCQ
1−phenyl−2−chloropropane on treating with alc. KOH gives mainly:
- A1-phenylpropene
- B2-phenylpropene
- C1-phenylpropane-2-ol
- D1-phenylpropan-1-ol
Explanation:
1−phenyl−2−chloropropane on treating with alc. KOH gives mainly 1−phenylpropene. This is dehydrochlorination reaction.
The double bond in the product is in conjugation with benzene ring.1−phenyl−2−chloropropane.
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On the basis of standard electrode potential, predict which of the following reaction can not occur ?
$A \to B$ ${k_1} = {10^{15}}{e^{ - 25000/8.34\,T}}$
$C \to D$ ${k_2} = {10^{14}}{e^{ - 15000/8.34\,T}}$
Calculate the approximate temperature at which $k_1 = k_2$ ...... $K$
$\begin{matrix}
{{O}_{3}}/Zn \\
(1) \\
\end{matrix}\,\,\,\,\,\,\,\,\,\,\begin{matrix}
EtONa/EtOH/\Delta \\
(2) \\
\end{matrix}\,\,\,\,\,\,\,\,\,\,\,\begin{matrix}
NaOCl \\
(3) \\
\end{matrix}\,\,\,\,\,\,\,\,\,\begin{matrix}
{{H}^{+}} \\
(4) \\
\end{matrix}$