MCQ
$2 \sin ^2 30^{\circ} \cdot \cot 30^{\circ}-3 \cos ^2 60^{\circ} \sec ^2 30^{\circ}=$
- A$\frac{\sqrt{3}-1}{2}$
- ✓$\frac{\sqrt{3}-2}{2}$
- C$0$
- D1
✓
Answer
Correct option: B.
$\frac{\sqrt{3}-2}{2}$
$\frac{\sqrt{3}-2}{2}$
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