Download App

Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
MCQ
$2 \sin \frac{5 \pi}{12} \cos \frac{\pi}{12}=$
  • ✓
    $\frac{2+\sqrt{3}}{2}$
  • B
    $\frac{2-\sqrt{3}}{2}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{3}{2}$
✓

Answer

Correct option: A.
$\frac{2+\sqrt{3}}{2}$
(A)
$2 \sin \frac{5 \pi}{12} \cos \frac{\pi}{12}=\sin \left(\frac{5 \pi}{12}+\frac{\pi}{12}\right)+\sin \left(\frac{5 \pi}{12}-\frac{\pi}{12}\right)$
$=\sin \frac{\pi}{2}+\sin \frac{\pi}{3}$
$=1+\frac{\sqrt{3}}{2}=\frac{2+\sqrt{3}}{2}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Trigonometry – II→Trigonometry – II — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

The smallest positive angle which satisfies the equation ​$2\sin^2\text{x}+\sqrt{3}\cos\text{x}+1=0$ is :
→
The value of $\sin600^{\circ}\cos330^{\circ}+\cos120^{\circ}\sin150^{\circ}$ is
→
Two sides of a rhombus are along the lines, x - y + 1 = 0 and 7x - y - 5 = 0 If its diagonals intersect at (-1,-2), then which one of the following is a vertex of this rhombus?
→
If $f (x)=\left\{\begin{array}{c} ax ^2- b , \text { when } 0 \leq x<1 \\ 2, \text { when } x=1 \\ x+1, \text { when } l < x \leq 2\end{array}\right.$ is continuous at
$x=1$, then the most suitable values of $a , b$ are
→
If circles $x^2+y^2-4 x-6 y+9=0$ and $x^2+y^2+2 x+2 y-7=0$ touch each other, then their point of contact is
→
In a $\triangle\text{ABC},$ if $a = 2, \angle\text{B}=60^{\circ}$ and $\angle\text{C}=75^{\circ},$ then $b =$
→
A problem in mathematics is given to 4 students whose chances of solving individually are $\frac{1}{2}, \frac{1}{3}, \frac{1}{4}$ and $\frac{1}{5}$. Then probability that the problem will be solved at least by one student is
→
If in a group of $n$ distinct objects, the number of arrangements of $4$ objects is $12$ times the number of arrangements of $2$ objects, then the number of objects is :
→
$\frac{\cos \left(90^{\circ}+\theta\right) \sec (-\theta) \tan \left(180^{\circ}-\theta\right)}{\sin \left(360^{\circ}+\theta\right) \sec \left(180^{\circ}+\theta\right) \cot \left(90^{\circ}-\theta\right)}=$
→
$\lim _{x \rightarrow 0} \frac{x\left( e ^{\sin x}-1\right)}{1-\cos x}$ is equal to
→