MCQ
$2 x^3-6 x+5$ is an increasing function, if
  • A
    0 < x < 1
  • B
    -1 < x < 1
  • $x<-1$ or $x>1$
  • D
    -1 < x < $-\frac{1}{2}$

Answer

Correct option: C.
$x<-1$ or $x>1$
(c) : Let $f(x)=2 x^3-6 x+5$
On differentiating w.r.t. $x$, we get $f^{\prime}(x)=6 x^2-6$
Since, it is increasing function.
$
\begin{array}{l}
\Rightarrow \quad 6 x^2-6>0 \Rightarrow(x-1)(x+1)>0 \\
\Rightarrow \quad x>1 \text { or } x<-1
\end{array}
$

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