MCQ
$20 \mu \mathrm{A}$ current flows for 30 seconds in a wire, transfer of charge will be
  • A
    $2 \times 10^{-4} \mathrm{C}$
  • B
    $4 \times 10^{-4} \mathrm{C}$
  • $6 \times 10^{-4} \mathrm{C}$
  • D
    $8 \times 10^{-4} \mathrm{C}$

Answer

Correct option: C.
$6 \times 10^{-4} \mathrm{C}$
(c) $Q=i t=20 \times 10 \times 30=6 \times 10^{-4} \cdot C$

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