MCQ
$2,\,2-$ Dimethylpropanoic acid on heating with sodalime gives
- A$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,\,C{H_3}\,}
\end{array}$ - B$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}\,} \\
{|\,\,} \\
{C{H_3} - C = C{H_2}}
\end{array}$ - ✓$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}\,\,} \\
{|\,\,\,\,\,\,} \\
{C{H_3} - CH - C{H_3}}
\end{array}$ - D$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,\,OH\,}
\end{array}$
