Question
$^{22}Ne$ nucleus, after absorbing energy, decays into two $\alpha-$particles and an unknown nucleus. The unknown nucleus is:
✓
Answer
$^{22}Ne$ decays
$\alpha$ particle $= He^{2+}$
Mass $No = 4$
$p = 2, n = 2$
So, New mass no. $= 22 − 8 = 14$
Atomic No. $= 10 − 4 = 6$
So, the new element is $_{6}C^{14}$
$\alpha$ particle $= He^{2+}$
Mass $No = 4$
$p = 2, n = 2$
So, New mass no. $= 22 − 8 = 14$
Atomic No. $= 10 − 4 = 6$
So, the new element is $_{6}C^{14}$
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