MCQ
$23\, g$ of sodium will react with methyl alcohol to give
- Aone mole of oxygen
- B$22.4\, dm^3$ of hydrogen gas at $NTP$
- C$1\, mole$ of $H_2$
- ✓$1 1.2 \,L$ of hydrogen gas at $NTP$

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The time taken for $A$ to become $1 / 4^{\text {th }}$ of its inital concentration is twice the time taken to become $1 / 2$ of the same. Also, when the change of concentration of $B$ is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is . . . . .