MCQ
$2\sin A{\cos ^3}A - 2{\sin ^3}A\cos A = $
- A$\sin 4A$
- ✓$\frac{1}{2}\sin 4A$
- C$\frac{1}{4}\sin 4A$
- Dએકપણ નહિ.
$ = 2\sin A\cos A({\cos ^2}A - {\sin ^2}A)$
$ = 2\sin A\cos A\cos 2A $
$= \sin 2A\cos 2A $
$= \frac{1}{2}\sin 4A$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.