MCQ
$2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right) = $
- A${\tan ^{ - 1}}\left( {\frac{{49}}{{29}}} \right)$
- B$\frac{\pi }{2}$
- C$0$
- ✓$\frac{\pi }{4}$
$ = {\tan ^{ - 1}}\frac{3}{4} + {\tan ^{ - 1}}\frac{1}{7} = {\tan ^{ - 1}}\left( {\frac{{(3/4) + (1/7)}}{{1 - (3/4) \times (1/7)}}} \right)$
$ = {\tan ^{ - 1}}\left( {\frac{{25}}{{25}}} \right) = \frac{\pi }{4}$.
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$\overrightarrow{\mathrm{a}} \times\{(\overrightarrow{\mathrm{r}}-\overrightarrow{\mathrm{b}}) \times \overrightarrow{\mathrm{a}}\}+\overrightarrow{\mathrm{b}} \times\{(\overrightarrow{\mathrm{r}}-\overrightarrow{\mathrm{c}}) \times \overrightarrow{\mathrm{b}}\}+\overrightarrow{\mathrm{c}} \times\{(\overrightarrow{\mathrm{r}}-\overrightarrow{\mathrm{a}}) \times \overrightarrow{\mathrm{c}}\}=\overrightarrow{0}$
નું સમાધાન કરે છે તો $\overrightarrow{\mathrm{r}}$ મેળવો.