MCQ
$3\  m \times\left(2\  m^2-5\  m n+4\  n^2\right)$ is equal to
  • A
    $6\  m^3+15\  m^2 n-12\  m n^2$
  • $6\  m^3-15\  m^2 n+12\  m n^2$
  • C
    $6\  m^3-15\  m^2 n-12\  m n^2$
  • D
    $6\  m^3+15\  m^2 n+12\  m n^2$

Answer

Correct option: B.
$6\  m^3-15\  m^2 n+12\  m n^2$
$3\  m \times\left(2\  m^2-5\  m n+4\  n^2\right)$
$=6\  m^3-15\  m^2 n+12\  m n^2$

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