MCQ
$3 x^2-6 x+5$ is an increasing function, if
  • A
    0 < x < 1
  • B
    -1 < x < 1
  • $x>1$
  • D
    -1 < x < $-\frac{1}{2}$

Answer

Correct option: C.
$x>1$
(c) : Let $f(x)=3 x^2-6 x+5$
Differentiating w.r.t. $x$, we get $f^{\prime}(x)=6 x-6$
Since, it is increasing function.
$
\Rightarrow 6 x-6>0 \Rightarrow(x-1)>0 \Rightarrow x>1
$

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