Question
✓
Answer
$AB \times AB = 6AB..... (i)$
Here,
$B \times B$ is a number whose unit’s digit is $B.$
Therefore, $B = 1$ or $5$
Again,
$AB \times AB = 6AB$
The square of a two digit number is a three digit number.
So, A can take values $1, 2 \& 3.$
For $A = 1, 2, 3$ and $B = 1$ Eq. $(i)$ is not satisfied.
Now, for $? = 1, B = 5$ Eq. $(i)$ is not satisfied.
$A = 2, B = 5$ satisfies the Eq. $(i)$
Hence, $A = 2, B = 5$
Here,
$B \times B$ is a number whose unit’s digit is $B.$
Therefore, $B = 1$ or $5$
Again,
$AB \times AB = 6AB$
The square of a two digit number is a three digit number.
So, A can take values $1, 2 \& 3.$
For $A = 1, 2, 3$ and $B = 1$ Eq. $(i)$ is not satisfied.
Now, for $? = 1, B = 5$ Eq. $(i)$ is not satisfied.
$A = 2, B = 5$ satisfies the Eq. $(i)$
Hence, $A = 2, B = 5$
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