MCQ
$[(-3)^2]^3$ is equal to:
- A$(-3)^8$
- ✓$(-3)^6$
- C$(-3)^5$
- D$(-3)^{23}$
We know that, if $‘a’$ is a rational number, m and n are natural numbers, then.
$(a^m)^n = a^{m \times n}$
So, $[(-3)^2 ]^3$
$= (-3)^{2 \times 3}$
$= (-3)^6$
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