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Exponents and Powers — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSExponents and Powers1 Mark
Question
$(-4)^{-4}× (4)^{-1}= (4)^5$
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Answer

$LHS = (-4)^{-4}× (4)^{-1}$
Using law of exponents, $a^{m}× a^n= (a)^{m+n}[\because$ a is non-zero integer$]$
$\therefore$ $(-4)^{-4}× (4)^{-1}= (4)^{-4}× (4)^{-1}$
$= (-4)^{-4-1}$
$= (-4)^{-5}$
$LHS ≠ RHS$

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