4 -Pentenoic acid when treated with I_2 and NaHCO_3 gives - Vidyadip

MCQ

$4$ -Pentenoic acid when treated with $I_2$ and $NaHCO_3$ gives

A
$4, 5$ -diiodopentanoic acid
✓
$5$ -iodomethyl-dihydrofuran- $2$ -one
C
$5$ -iodo-tetrahydropyran- $2$ -one
D
$4$ -pentenolyiodide

✓

Answer

Correct option: B.

$5$ -iodomethyl-dihydrofuran- $2$ -one

b
$(b)$ Iodo lactonization.

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