MCQ
5C0 + 2.5C1 + 22.5C2 + 23.5C3 + 24.5C4 + 25.5C5 =
- A32
- B243
- C64
- D729
Solution
Just calculate it by substituting the values of 5C1, 5C2 etc as 5, 10 and just add them to get 243.
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The area of a triangle with vertices at (-4, -1), (1, 2) and (4, -3) is: