MCQ
$6.24 \times 10^{19}$ electrons is equal approximately to:
- ✓$10$ coulombs.
- B$96500$ coulombs.
- Cone electron volt.
- D$0.1F.$
✓
Answer
Correct option: A.
$10$ coulombs.
Since $ 6.24 \times 10^{18}$ electrons $= 1$ coulomb
$\therefore 6.24 \times 10^{19}$ electrons $= 10$ coulomb
$\Big(\frac{6.24\times10^{19}}{6.24\times10^{18}}\Big)$
$\therefore 6.24 \times 10^{19}$ electrons $= 10$ coulomb
$\Big(\frac{6.24\times10^{19}}{6.24\times10^{18}}\Big)$
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