Question
✓
Answer
Roots are distinct and real when $b^2-4 a c=5$, not real when $b^2-4 a c=-5$.
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Complete the following activity to find the 19th term of the A.P. 10, 15, 20,..........
Complete the following activity to determine the nature of the root of the quadratic equation $x^2 + 2x + 9 = 0$.
Compare $x^2+ 2x + 9 = 0$ with $ax^2 + bx + c = 0$.
→Compare $x^2+ 2x + 9 = 0$ with $ax^2 + bx + c = 0$.
Write the values of the following trigonometric ratios.
$\cos 30^{\circ}=\frac{⬜}{⬜}$
→→$\cos 30^{\circ}=\frac{⬜}{⬜}$
Complete the following table using given information.
A die is rolled. Complete the following activity to find the probability of getting a prime number on the upper face of the die :
A die is rolled. S is the sample space.
A die is rolled. S is the sample space.
Prove that $\cos ^2 \theta \cdot\left(1+\tan ^2 \theta\right)=1$. complete the activity given below.
Activity:
$ \text { L.H.S }=\square$
$=\cos ^2 \theta \times \square \ldots . .\left[1+\tan ^2 \theta=\square\right]$
$=(\cos \theta \times \square)^2$
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$=1$
$=\text { R.H.S } $
→→Activity:
$ \text { L.H.S }=\square$
$=\cos ^2 \theta \times \square \ldots . .\left[1+\tan ^2 \theta=\square\right]$
$=(\cos \theta \times \square)^2$
$=1^2$
$=1$
$=\text { R.H.S } $
Smita has invested ₹ 12,000 and purchased shares of FV ₹ 10 at a premium of ₹ 2. Find the number of shares she purchased. complete the given activity to get the answer.
FV = ₹ 10, Premium = ₹ 2
∴ MV = FV + ⬜
= ⬜ + ⬜ = ⬜
$\therefore \quad$ No. of shares $=\frac{\text { Totalinvestment }}{ MV }=$ = $=\frac{12000}{⬜}$
= ⬜ shares
Smita has purchased ⬜ shares.
→FV = ₹ 10, Premium = ₹ 2
∴ MV = FV + ⬜
= ⬜ + ⬜ = ⬜
$\therefore \quad$ No. of shares $=\frac{\text { Totalinvestment }}{ MV }=$ = $=\frac{12000}{⬜}$
= ⬜ shares
Smita has purchased ⬜ shares.
Write the correct number in the given boxes from the following A. P.
– 3, – 8, – 13, – 18, . . .
Here
$t _3$ = ⬜, $t _2$ = ⬜, $t _4$ = ⬜, $t _1$ = ⬜
$t _2- t _1$ = ⬜, $t _3- t _2$ = ⬜
∴ a = ⬜, d = ⬜
→– 3, – 8, – 13, – 18, . . .
Here
$t _3$ = ⬜, $t _2$ = ⬜, $t _4$ = ⬜, $t _1$ = ⬜
$t _2- t _1$ = ⬜, $t _3- t _2$ = ⬜
∴ a = ⬜, d = ⬜