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Find the correct answer from the alternatives given.
The persons of O- blood group are 40%. The classification of persons based on blood groups is to be shown by a pie diagram. What should be the measures of angle for the persons of O- blood group?
A. 114°
B. 140°
C. 104°
D. 144°
The persons of O- blood group are 40%. The classification of persons based on blood groups is to be shown by a pie diagram. What should be the measures of angle for the persons of O- blood group?
A. 114°
B. 140°
C. 104°
D. 144°
The following table shows the number of students and the time they utilized daily for their studies. Find the mean time spent by students for their studies by direct method.
From the figure given alongside, find the length of the median AD of triangle ABC. Complete the activity.
Solution:
Here $A(-1,1), B(5,-3), C(3,5)$ and suppose $D(x, y)$ are coordinates of point $D$.
Using midpoint formula,
$ x=\frac{5+3}{2}$
$\therefore x=\square$
$y=\frac{-3+5}{2}$
$\therefore y=\square $
Using distance formula,
$ \therefore A D=\sqrt{(4-\square)^2+(1-1)^2}$
$\therefore A D=\sqrt{(\square)^2+(0)^2}$
$\therefore A D=\sqrt{\square} $
$\therefore$ The length of median $A D=\square$
→Solution:
Here $A(-1,1), B(5,-3), C(3,5)$ and suppose $D(x, y)$ are coordinates of point $D$.
Using midpoint formula,
$ x=\frac{5+3}{2}$
$\therefore x=\square$
$y=\frac{-3+5}{2}$
$\therefore y=\square $
Using distance formula,
$ \therefore A D=\sqrt{(4-\square)^2+(1-1)^2}$
$\therefore A D=\sqrt{(\square)^2+(0)^2}$
$\therefore A D=\sqrt{\square} $
$\therefore$ The length of median $A D=\square$
Find the correct answer from the alternatives given. Different expenditures incurred on the construction of a building were shown by a pie diagram. The expenditure $Rs. 45,000$ on cement was shown by a sector of central angle of $75^\circ$ . What was the total expenditure of the construction?
→From fig., seg $PQ ||$ side $BC, AP = x + 3, PB = x – 3, AQ = x + 5, QC = x – 2,$ then complete the activity to find the value of $x.$
$\text { In } \triangle P Q B, P Q|| \text { side } B C$
$\frac{ AP }{ PB }=\frac{ AQ }{[} \quad \ldots[\ldots]$
$\frac{x+3}{x-3}=\frac{x+5}{[}$
$(x+3)[\quad]=(x+5)(x-3)$
$x^2+x-[\quad]=x^2+2 x-15$
$x=[$
→$\text { In } \triangle P Q B, P Q|| \text { side } B C$
$\frac{ AP }{ PB }=\frac{ AQ }{[} \quad \ldots[\ldots]$
$\frac{x+3}{x-3}=\frac{x+5}{[}$
$(x+3)[\quad]=(x+5)(x-3)$
$x^2+x-[\quad]=x^2+2 x-15$
$x=[$
A frequency distribution of funds collected by 120 workers in a company for the drought affected people are given in the following table. Find the mean of the funds by 'step deviation' method.
The prices of different articles and demand for them is shown in the following frequency distribution table. Find the median of the prices.
Complete the following table.
| No. | Equation | Is the equation a linear equation in 2 variables ? |
| 1 | 4m+3n=12 | Yes |
| 2 | 3x^(2)-7y=13 | |
| 3 | sqrt2x-sqrt5y=16 | |
| 4 | 0x+6y-3=0 | |
| 5 | 0.3 x+0y-36=0 | |
| 6 | (4)/(x)+(5)/(y)=4 | |
| 7 | 4xy-5y-8=0 |
The weekly wages of 120 workers in a factory are shown in the following frequency distribution table. Find the mean of the weekly wages.
