MCQ
$8\sin\frac{\text{x}}{8}\cos\frac{\text{x}}{2}\cos\frac{\text{x}}{4}\cos\frac{\text{x}}{8}$ is equal to:
  • A
    $8\cos\text{x}$
  • B
    $\cos\text{x}$
  • C
    $8\sin\text{x}$
  • $\sin\text{x}$

Answer

Correct option: D.
$\sin\text{x}$
we have,
$=8\sin​​\text{x}8\cos\text{x}2\cos\text{x}4\cos\text{x}8$
$=4\times2\sin\text{x}8\cos\text{x}2\cos\text{x}2$
$=4\times\sin\text{x}\cos\text{x}2\cos\text{x}4$
$=2\times2\sin\text{x}4\cos\text{x}4\cos\text{x}2$
$=2\times\sin2\cos\text{x}2$
$=\sin\text{x}$

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