MCQ
$8\sin\frac{\text{x}}{8}\cos\frac{\text{x}}{2}\cos\frac{\text{x}}{4}\cos\frac{\text{x}}{8}$ is equal to:
- A$8\cos\text{x}$
- B$\cos\text{x}$
- C$8\sin\text{x}$
- ✓$\sin\text{x}$
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