Question
$98+4A=CB3$

Answer

$A = 5$ as $8 + 5 = 13$.
We want $3$ at units place and $1$ is carry over.
Now $9 + 4 + 1 = 14.$
$B = 4$ and $C = 1$
Hence $A = 5$ and $B = 4$ and $C = 1$
$98+ 45=143$

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