$V = iR$
$ \Rightarrow $ $5 = \left( {\frac{{110}}{{20 \times {{10}^3} + R}}} \right) \times 20 \times {10^3}$
$ \Rightarrow $ ${10^5} + 5R = 22 \times {10^5}$
$ \Rightarrow $ $R = 21 \times \frac{{{{10}^5}}}{5} = 420\,K\Omega $
$Y :$ The resistivity of a semiconductor decreases with increases of temperature.
$Z :$ In a conducting solid, the rate of collision between free electrons and ions increases with increase of temperature.
Select the correct statement from the following :



[Voltage distribution $V(t)$ is shown by Fig. $(1)$ and the circuit is shown in Fig. $(2)$]