A $5\, kg$ collar is attached to a spring of spring constant $500\, Nm^{-1}$. It slides without friction over a horizontal rod. The collar is displaced from its equillibrium position by $10\, cm$ and released. The time period of oscillation is
A$\frac{\pi }{5}\,s$
B$\frac{\pi }{2}\,s$
C$\pi \,s$
D$2\pi \,s$
Medium
Download our app for free and get started
A$\frac{\pi }{5}\,s$
a $\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{K}}}=\sqrt{\frac{5}{500}}=\frac{2 \pi}{10}=\frac{\pi}{5} \mathrm{s}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A particle executes $S.H.M$ between $x =\, -A$ to $x =\, +A$ . The time taken for it in going from $0$ to $A/2$ is $T_1$ and from $A/2$ to $A$ is $T_2$. Then
Time period of a particle executing $SHM$ is $8\, sec.$ At $t = 0$ it is at the mean position. The ratio of the distance covered by the particle in the $1^{st}$ second to the $2^{nd}$ second is :
Which of the following expressions corresponds to simple harmonic motion along a straight line, where $x$ is the displacement and $a, b, c$ are positive constants?
A mass $m$ is suspended separately by two different springs of spring constant $K_1$ and $K_2$ gives the time-period ${t_1}$ and ${t_2}$ respectively. If same mass $m$ is connected by both springs as shown in figure then time-period $t$ is given by the relation