MCQ
$'A'$ and $'B'$ in the following reactions are ${image}$


- A

- B

- ✓

- D








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$CS_2 + 3O_2 \to 2SO_2 + CO_2$
Reason : $\overset{\centerdot \,\,\centerdot }{\mathop{N}}\,{{H}_{2}}$ is more electron donating than $\overset{\centerdot \,\centerdot \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{O{{C}_{2}}{{H}_{5}}}}\,$
Consider the above reactions, identify product $B$ and product $\mathrm{C}$
$Zn^{2+} + 2e^-$ $\longrightarrow$ $Zn (s) ; E^o = -0.76\,V$
$Ca^{2+} + 2e^-$ $\longrightarrow$ $Ca (s) ; E^o = -2.87\,V$
$Mg^{2+} + 2e^-$ $\longrightarrow$ $Mg (s) ; E^o = -2.36\,V$
$Ni^{2+} + 2e^-$ $\longrightarrow$ $Ni (s) ; E^o = -0.25\,V$
The reducing power of the metals increases in the order