MCQ
$(A)$ and $(B)$ in the following reactions are
- ✓
- B
- C
- D$(A)\, =\,RR'CH_2CN \,;\, (B)\, = \,NaOH$
✓
Answer
Correct option: A.
a
$\begin{array}{*{20}{c}}
O \\
{||} \\
{R - C - {R^1}}
\end{array}$ $\xrightarrow{{HCN}}$ $\begin{array}{*{20}{c}}
{\,\,\begin{array}{*{20}{c}}
{OH} \\
{|\,\,\,\,}
\end{array}} \\
{R - C - {R^1}} \\
{|\,\,} \\
{\,\,CN}
\end{array}$ $\xrightarrow{{LiAl{H_4}}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
{\,|\,\,\,}
\end{array}} \\
{R - C - {R^1}} \\
{|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - N{H_2}\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
O \\
{||} \\
{R - C - {R^1}}
\end{array}$ $\xrightarrow{{HCN}}$ $\begin{array}{*{20}{c}}
{\,\,\begin{array}{*{20}{c}}
{OH} \\
{|\,\,\,\,}
\end{array}} \\
{R - C - {R^1}} \\
{|\,\,} \\
{\,\,CN}
\end{array}$ $\xrightarrow{{LiAl{H_4}}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
{\,|\,\,\,}
\end{array}} \\
{R - C - {R^1}} \\
{|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - N{H_2}\,\,\,\,}
\end{array}$
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