MCQ
$A$ and $B$ in the following reactions are
- ✓
- B
- C
- D$A = RR'C{H_2}CN,B = NaOH$
✓
Answer
Correct option: A.
a
(a) $R - CO - R\,'\xrightarrow{{HCN}}$ - $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
|
\end{array}} \\
{R - C - R'} \\
{|\,\,} \\
{\,\,\,\,CN}
\end{array}\xrightarrow{{LiAl{H_4}}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OH}\,\, \\
|
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{R - C - C{H_2}N{H_2}} \\
\,\,\, {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,R'\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
(a) $R - CO - R\,'\xrightarrow{{HCN}}$ - $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,OH} \\
|
\end{array}} \\
{R - C - R'} \\
{|\,\,} \\
{\,\,\,\,CN}
\end{array}\xrightarrow{{LiAl{H_4}}}$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,OH}\,\, \\
|
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{R - C - C{H_2}N{H_2}} \\
\,\,\, {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,R'\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Sea water contains $29.25 \%$ $NaCl$ and $19 \% \,MgCl _2$ by weight of solution. The normal boiling point of the sea water is $..........{ }^{\circ} C$ (Nearest integer)
→Assume $100 \%$ ionization for both $NaCl$ and $MgCl _2$
Given : $K _{ b }\left( H _2 O \right)=0.52\,K\,kg\,mol ^{-1}$
Molar mass of $NaCl$ and $MgCl _2$ is 58.5 and $95\,g$ $mol ^{-1}$ respectively.
Two unknown compounds $X$ and $Y$, both having molecular formula $C_4 H_8O$ give following results with four chemical tests.
→| Bromine | $Na$ metal | Chromic acid | Lucas reagent | |
| Compound $X$ | decolourises | bubbles | Orange to Green | No reaction |
| Compound $Y$ | No reaction | No reaction | No reaction | No reaction |
Compound $X$ and $Y$ respectively are
A bromoalkane $'X'$ reacts with magnesium in dry ether to form compound $'Y'$. The reaction of $'Y'$ with methanol followed by hydrolysis yield an alcohol having molecular formula, $C_{4} H_{10} O$. The compound $'X'$ is
→A mixture has $18\,g$ water and $414\,g$ ethanol. The mole fraction of water in mixture is (assume ideal behaviour of the mixture)
→Correct statement regarding molecules $SF_4,\, CF_4$ and $XeF_4$ are
→The main product of following reaction will be
The major product obtained in the following reactions is”
The standard electrode potential is measured by
Which of the following ions has the highest magnetic moment
Low spin complex of $d^6-$ cation in an octahedral field will have the following energy
→($\Delta _o =$ crystal field splitting energy in an octahedral field, $P =$ Electron pairing energy)