Question
$A \rightarrow B$
$\sim B$
$\therefore \sim A$

Answer

Combining the two bases of this argument as a whole, the argument will be as follows:
$(A \rightarrow B)\ \&\ \sim B$
$\therefore \sim A$
Truth Table:
  Support Statement The resulting statement
  $1$ $2$ $3$ $4$ $5$ $6$
$A$ $B$ $\sim B$ $A \rightarrow B$ $(A \rightarrow B)\ \&\ \sim B$ $\sim A$
$1$ $T$ $T$ $F$ $T$ $F$ $F$
$2$ $T$ $F$ $T$ $F$ $F$ $F$
$3$ $F$ $T$ $F$ $T$ $F$ $T$
$4$ $F$ $F$ $T$ $T$ $T^*$ $T^*$
  $2 (\sim )$ $1, 2 (\rightarrow)$ $4,3 (\&)$ $1(\sim )$
               
Judgment of the validity of the argument: A total of six columns have been formed in the above fact sheet. In which the column no. Base statement and column no. $6$ is the representation of the result statement. Out of the total four rows of the truth table, only rows. The base statement in $4$ is the truth $‘T’$ and the result statement in the same row is also the truth $‘T’.$ Hence this argument is standard.

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