Question
$A B\times5C A B$
✓
Answer
As we need $\text{B}$ at unit place and $\text{A}$ at ten’s place,
$B = 0$ as $5 \times 0 = 0$
Now we want to find $\text{A}, 5 \times \text{A = A}($at unit’s place$)$
$\text{A} = 5,$ as $ 5 \times 5 = 25$
$\text{C} = 2$
$50\times 5=2 5 0$
$B = 0$ as $5 \times 0 = 0$
Now we want to find $\text{A}, 5 \times \text{A = A}($at unit’s place$)$
$\text{A} = 5,$ as $ 5 \times 5 = 25$
$\text{C} = 2$
$50\times 5=2 5 0$
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