Rajasthan BoardEnglish MediumSTD 9ScienceGravitation3 Marks
Question
A ball thrown up vertically returns to the thrower after $6s$. Find the maximum height it reaches.
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Answer
Let the maximum height attained by the ball be h.
Initial velocity during the upward journey$, u = 29.4\ m s^{-1}$
Final velocity $, v = 0$
Acceleration due to gravity$, g = -9.8\ m s^{-2}$
From the equation of motion$, s = ut + 1/2 \ at^2$
$h = 29.4 \times 3 + 1/2 \times -9.8 \times (3)^2 = 44.1m$
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