- ✓Basic
- BAcid
- CNeutral
- DBoth $(a) $ and $(b)$
$pOH = - \log \,\,[O{H^ - }]$ $ = - \log \,\,[5 \times {10^{ - 2}}]$
$pOH = 1.30$; $pH + pOH = 14$
$pH = 14 - pOH $ $ = 14 - 1.30 = 12.7$
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The transition temperature for $\alpha$ to $\beta$ phase change is $600 \mathrm{~K}$ and $C_{p, \beta}-C_{p, \alpha}=1 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$. Assume $\left(C_{p, \beta}-C_{p, \alpha}\right)$ is independent of temperature in the range of 200 to $700 \mathrm{~K} . \mathrm{C}_{p, \alpha}$ and $C_{p, \beta}$ are heat capacities of $\alpha$ and $\beta$ phases, respectively.
($1$)The value of entropy change, $\mathrm{S}_\beta-\mathrm{S}_\alpha$ (in $\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$ ), at $300 \mathrm{~K}$ is. . . . . . .
[Use : $\ln 2=0.69$ Given : $S_\beta-S_\alpha=0$ at $\left.0 \mathrm{~K}\right]$
($2$) The value of enthalpy change, $\mathrm{H}_\beta-\mathrm{H}_\alpha$ (in $J$ mol ${ }^{-1}$ ), at $300 \mathrm{~K}$ is
Give the answer quetion ($1$) and ($2$)
The value of $x$ is
$(i)$ $4.5\, mL$ $\quad (ii)$ $4.5\, mL$ $\quad (iii)$ $4.4\, mL$
$(iv)$ $4.4\, mL$ $\quad (v)$ $4.4\, mL$
If the volume of oxalic acid taken was $10.0 \,mL$ then the molarity of the $NaOH$ solution is .... $M.$ (Rounded-off to the nearest integer)