A battery of  $24\,cells$ , each of emf  $1.5\,V$  and internal resistance $2\,\Omega$ is to be connected in order to send the maximum current through a $12\,\Omega$ resistor. The correct arrangement of cells will be 
Diffcult
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Suppose $m$ rows are connected in parallel and each row contain $n$ identical cells (each cell

having $E=15 \mathrm{V}$ and $r=2 \Omega$ ) For maximum current in the external resistance $R,$ the neccessary

is $R=\frac{n r}{m} \Rightarrow 12=\frac{n \times 2}{m} \Rightarrow n=6 m$

Total cells $=24=n \times m$

On solving equation (i) and (ii) $n=12$ and $m=2$

i.e. 2 rows of 12 cells are connected in series.

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