MCQ
A body executing simple harmonic motion has a maximum acceleration equal to $ 24\,metres/se{c^2} $ and maximum velocity equal to $ 16\;metres/sec $. The amplitude of the simple harmonic motion is
  • $\frac{{32}}{3}\,metres$
  • B
    $\frac{3}{{32}}\,metres$
  • C
    $\frac{{1024}}{9}\,metres$
  • D
    $\frac{{64}}{9}\,metres$

Answer

Correct option: A.
$\frac{{32}}{3}\,metres$
a
(a) Maximum velocity $ = a\omega = 16$ 

Maximum acceleration $ = {\omega ^2}a = 24$ 

$ \Rightarrow a = \frac{{{{(a\omega )}^2}}}{{{\omega ^2}a}} = \frac{{16 \times 16}}{{24}} = \frac{{32}}{3}m$

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