MCQ
A body moving with uniform acceleration has velocities $20\ ms^{-1}$ and $30\ ms^{-1}$.when passing two points $A$ and $B$ . Then the velocity midway between $A$ and $B$ is:
  • $25.5\ ms^{-1}$
  • B
    $24\ ms^{-1}$
  • C
    $25\ ms^{-1}$
  • D
    $10 \sqrt{6}\ ms^{-1}$

Answer

Correct option: A.
$25.5\ ms^{-1}$
Let the acceleration of the car is $= a$
And the distance between $A$ and $B$ is $= d$
$V^2-u^2=2ad$
$V=30\ m / s$ and $u=20\ m / s$
$2 ad=30^2-20^2$
$Ad=\frac{(900-400)}{2}=250$
When the car is at the mid point of $AB$ then let the speed of the car is $V _1$
$V_1^2-20^2=2 a\left(\frac{d}{2}\right)$
$V_1^2=ad+400$
$=250+400$
$=650$
therefore $V _1$ is $=25.4950\ m / s$.

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