Question
A box contains $5$ strawberry chocolates, $6$ coffee chocolates and $2$ peppermint chocolates. Find the probability of each of the following events, if one of the chocolates is picked from the box at random. (i) it is a coffee chocolate. (ii) it is a peppermint chocolate.

Answer

Sample space is ' $S$ ' and $n(S)=5+6+2=13$
$\text { Event A : it is a coffee chocolate }$
$\therefore \quad \mathrm{n}(\mathrm{A})=6$
$\therefore \quad \mathrm{P}(\mathrm{A})=\frac{\mathrm{n}(\mathrm{A})}{\mathrm{n}(\mathrm{S})}=\frac{6}{13}$
$\text { Event B : it is a peppermint chocolate }$
$\therefore \quad \mathrm{n}(\mathrm{B})=2$
$\therefore \quad \mathrm{P}(\mathrm{B})=\frac{\mathrm{n}(\mathrm{B})}{\mathrm{n}(\mathrm{S})}=\frac{2}{13}$

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