MCQ
A box contains $90$ discs, numbered from $1$ to $90$. If one disc is drawn at random from the box, the probability that it bears a prime number less than $23,$ is :
- A$\frac{7}{90}$
- B$\frac{10}{90}$
- ✓$\frac{4}{45}$
- D$\frac{9}{89}$
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