MCQ
A box contains $90$ discs, numbered from $1$ to $90$. If one disc is drawn at random from the box, the probability that it bears a prime number less than $23,$ is :
  • A
    $\frac{7}{90}$
  • B
    $\frac{10}{90}$
  • $\frac{4}{45}$
  • D
    $\frac{9}{89}$

Answer

Correct option: C.
$\frac{4}{45}$
Number of discs in a box $= 90$
Numbered on it are $1$ to $90$
Prime numbers less than $23$ are $= \{2, 3, 5, 7, 11, 13, 17, 19\} = 8$
Probability of a number being a prime less than $23=\frac{8}{90}=\frac{4}{45}$

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