Question
A capacitor is charged by using a battery which is then disconnected. A dielectric slab is introduced between the plates which results in:

Answer

  1. Decrease in the potential difference across the plates and reduction in the stored energy but no change in the charge on the plates.
Explanation:
If a dielectric slab of dielectric constant K is filled in between the plates of a capacitor after charging the capacitor (i.e., after removing the connection of battery with the plates of capacitor) the potential difference between the plates reduces to $\frac{1}{\text{K}}$​ times and the potential energy of capacitor reduces to$\frac{1}{\text{K}}$times but there is no change in the charge on the plates.

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