MCQ
A Carnot engine has an efficiency of $50 \%$ when its source is at a temperature $327^{\circ}\,C$. The temperature of the sink is $.........^{\circ} C$
- A$200$
- ✓$27$
- C$15$
- D$100$
$\% \eta=\left(1-\frac{T_{\text {sink }}}{T_{\text {source }}}\right) \times 100$
$T_{\text {source }}=327^{\circ}\,C =600\,K$
$50=\left(1-\frac{T_{\text {sink }}}{600}\right) \times 100$
$\frac{1}{2}=1-\frac{T_{\text {sink }}}{600}$
$T _{\text {Sink }}=300\,K$
So temp. of sink is ${ }^{\circ} C =300-2763=27^{\circ}\,C$
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[Take surface tension of water ${T}=7.3 \times 10^{-2} \, {Nm}^{-1}$, angle of contact $=0, {g}=10\, {ms}^{-2}$ and density of water $\left.=1.0 \times 10^{3} \,{kg} \,{m}^{-3}\right]$ (in $mm$)