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Thermodynamics — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsThermodynamics1 Mark
MCQ
A Carnot engine working between $300 \mathrm{~K}$ and $600 \mathrm{~K}$ has work output of $800 \mathrm{~J}$ per cycle. What is amount of heat energy supplied to the engine from source per cycle
  • A
    $1800 \mathrm{~J} / \mathrm{cycle}$
  • B
    $1000 \mathrm{~J} / \mathrm{cycle}$
  • C
    $2000 \mathrm{~J} / \mathrm{cycle}$
  • ✓
    $1600 \mathrm{~J} / \mathrm{cycle}$
✓

Answer

Correct option: D.
$1600 \mathrm{~J} / \mathrm{cycle}$
$\eta =\frac{T_1-T_2}{T_1}-\frac{W}{Q} \Rightarrow Q=\left(\frac{T_1}{T_1-T_2}\right) W$
$=\frac{600}{(600-300)} \times 800=1600 \mathrm{~J}$

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