MCQ
A common emitter amplifier is designed with NPN transistor (a = 0.99). The input impedance is 1 KW and load is 10 KW. The voltage gain will be
- A9.9
- B99
- ✓990
- D9900
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$\mathrm{V}=\mathrm{V}_{0} \sin \omega \mathrm{t}$
The displacement current between the plates of the capacitor, would then be given by :