It means $-CHO$ group is present.
It means only one $-CHO$ group is present.
${C_2}{H_5}OH + C{l_2} \to C{H_3}CHO + 2HCl$
$C{H_3}CHO + 3C{l_2} \to \mathop {CC{l_3}CHO}\limits_{{\rm{Chloral}}} + 3HCl$
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$I.$ In gaseous phase, the vapour pressure of $CH_3COOH$ is less than expected.
$II.$ In benzene, acetic acid dimerises.
$III.\, CH_3OH$ is more viscous than $H_2O.$
$IV.\, CH_3OCH_3$ is non-polar but soluble in water.
Select the correct set of codes using $T$ for true and $F$ for false statements in given sequence.
$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O$,
$E^{o} _{ Mn ^{2+} / MnO _{4}^{-}}=-1.510 \,V$
$\frac{1}{2} O _{2}+2 H ^{+}+2 e ^{-} \rightarrow H _{2} O$,
$E _{ O _{2} / H _{2} O }^{o}=+1.223 \,V$
Will the permanganate ion, $MnO _{4}^{-}$liberate $O _{2}$ from water in the presence of an acid ?