Question
A compound with empirical formula $AB$ has vapour density $3$ times its empirical formula weight. Find the molecular formula.

Answer

Since molecular mass is $2$ times the vapour density, so Mol. Mass $= 2 V.D$
Empirical formula weight $= V.D/3$
So, n = molecular mass/ Empirical formula weight = 6
Hence, the molecular formula is $A_6B_6$​​​​​​​

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