MCQ
A compound with empirical formula AB has vapour density three times its empirical formula. Its molecular formula will be:
  • A
    A6B6
  • B
    A2B4
  • C
    A2B4
  • D
    AB

Answer

A. $A _6 B_6$
Explanation:
Molecular formula $=($ Empirical formula $) \times n$
$n=\frac{\text { Molecular mass }}{\text { Empirical mass }} \ldots \text { (i) }$
Vapour density $=\frac{\text { Molecular mass }}{2}$
Molecular mass $=2 \times$ Vapour density. $\ldots(ii)$
From question: Vapour density $=3 \times$ Empirical Mass...(iii)
From (ii) and (iii),
Molecular mass $=2 \times 3 \times$ Empirical mass
Molecular mass $=6 \times$ Empirical mass
$6=\frac{\text { Molecular mass }}{\text { Empirical mass }} \ldots \text { (iv) }$
From (i) and (iv),
Molecular formula $=($ Empirical formula $) \times n$
$\begin{array}{l}
=(AB) \times n \\
=(AB) \times 6
\end{array}$
Molecular formula $= A _6 B_6$.

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